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# Displacement Time Calculator

## Online calculator for calculating the time of movement, calculates the time if you know: the distance traveled and speed, acceleration and speed, and also acceleration, speed and distance and gives a step by step solution. The calculator calculates: Time calculator, if known: distance traveled and speed.Time calculator, if known: acceleration and speed.Time calculator, if known: acceleration, speed and distance traveled.Time displacement calculation examples

Time Calculator, if Known: Distance Traveled and Speed

Time is equal to the ratio of distance to speed.
Distance
Speed

Time Calculator, if Known: Acceleration and Speed

If initial speed v0 is zero, put zero in the field for initial speed v0
Initial speed v0
Final speed v
Acceleration a

Time Calculator, if Known: Acceleration, Speed and Distance Traveled

If speed velocity v0 is zero, put zero in the field for initial speed v0
Initial speed v0
Distance S
Acceleration a

### Examples of Calculating Time if the Distance Traveled and Speed Are Known

Example 1.
The boat sailed 1736 yards at a speed of 60 Kilometers per hour. How long did the boat sail?

Step by step solution:
Convert yards to kilometers. One kilometer is 1093.61 yards, so we divide yards by 1093.61.
1736 : 1093.61 = 24800/15623 = 1.58740318760801 kilometers.

Find time, divide distance by speed.

 Time =
 24800/15623 60
 = 1240/46869 = 0.0264567197934669 hours

Time = 0 hours 1 minutes 35.2441912564808 seconds

Example 2.
The car, moving at a speed of 12 yards per second, covered a distance of 3000 kilometers. How long did the car drive?

Step by step solution:
Converting kilometers to yards. One kilometer is 1093.61 yards, so multiply kilometers by 1093.61.
3000 × 1093.61 = 3280830 yards.

Find time, divide distance by speed.

 Time =
 3280830 12
 = 546805/2 = 273402.5 seconds

Time = 75 hours 56 minutes 42.5000000000091 seconds

### Examples of calculating the time, if the acceleration and speed are known for a uniformly accelerated rectilinear motion

Example 1.
The aircraft moved uniformly accelerated with an acceleration of 25000 km/h2. Before takeoff, the aircraft's speed increased from 15 to 100 m/s2. Determine the time during which the airplane's speed increased from 15 to 100 m/s2.

Step by step solution:

Convert meter per second to kilometer per hour.

Let's convert meters to kilometers. There are 1000 meters in one kilometer, so we divide the meters by 1000.
15 : 1000 = 3/200 = 0.015 kilometers.

Let's convert seconds to hours.
There are 3600 seconds in one hour, so we need to divide the number of seconds by 3600.
1 : 3600 = 1/3600

Divide distance by time
 v0 = 3/200 1/3600
 = 54 Kilometers per hour

Convert meter per second to kilometer per hour.

Let's convert meters to kilometers. There are 1000 meters in one kilometer, so we divide the meters by 1000.
100 : 1000 = 1/10 = 0.1 kilometers.

Let's convert seconds to hours.
There are 3600 seconds in one hour, so we need to divide the number of seconds by 3600.
1 : 3600 = 1/3600

Divide distance by time
 v = 1/10 1/3600
 = 360 Kilometers per hour

Let's find the time, divide the difference between the final and initial speeds by acceleration.

 t =
 360 - 54 25000
 = 153/12500 = 0.01224 hours

Time = 0 hours 0 minutes 44.064 seconds

### Examples of calculating the time, if the acceleration, speed and distance traveled are known for a rectilinear uniformly accelerated motion

Example 1.
The cyclist, moving with a constant acceleration of 0.5 m/s2 and an initial speed of 30 km/h, drove down the mountain. Calculate the time taken by the cyclist to descend if the length of the slide was 120 meters.

Step by step solution:

Convert kilometer per hour to meter per second

Let's convert kilometers to meters. There are 1000 meters in one kilometer, so we multiply kilometers by 1000.
30 × 1000 = 30000 meters.

Let's convert hours into seconds.
There are 3600 seconds in one hour, which means we need to multiply the number of hours by 3600.
1 × 3600 = 3600

Divide distance by time
 v0 = 30000 3600
 = 25/3 = 8.33333333333333 Meters per second

Let's find the time, divide the difference between the final and initial speeds by acceleration.

 t = (25/3)2 + 2 × 120 × 0.5 - 25/3 0.5
 = 54305485480417/5000000000000 = 10.8610970960834 seconds

Time = 0 hours 0 minutes 10.8610970960834 seconds